obtain the equation of hyperbola in each of the following cases : foci at `(+-4,0)` and vertices at `(+-2,0)`.

Explanation

Here c=4 ,a=2 `therefore` b^2=c^2-a^2=12` `therefore` Eqn of the hyperbola is `x^2/a^2+y^2/b^2=1` or `x^2/4-y^2/12=1`