obtain the equation of hyperbola in each of the following cases: centre at (0,0) transverse axis along x-axis of length 4 and focus at `(2sqrt5,0)`.

Explanation

Here 2a=4 c=`2sqrt5` `therefore` a=2 `therefore` b^2=c^2-a^2=20-4=16 `therefore` Eqn of the ellipse is `x^2/a^2-y^2/b^2=1` or `x^2/4-y^2/16=1`