obtain the equation of hyperbola in each of the following cases: centre at (0,0) transverse axis is along y-axis the distance between the foci is 14 and distance between the vertices is 12.

Explanation

Here 2c =14 2a =12 `therefore` c=7 , a=6 `therefore` b^2=c^2-a^2=13` `therefore` Eqn of the ellipse is `y^2/a62-x^2/b^2=1` or `y^2/36-x^2/13=1`