obtain the equation of hyperbola in each of the following cases: centre (1,-2) transverse axis parallel to x-axis of length 6 and conjugate axis of length 10.

Explanation

Centre (1,-2) transverse axis parallel to x-axis of length 6 conjugate axis of length 10 .`therefore` 2a=6 , 2b=10 `therefore` a=3 , b=5 , h=1 , k=-2 `therefore` Eqn of the hyperbola
`(x-h)^2/a^2-(y-k)^2/b^2=1` or `(x-1)^2/9-(y-2)^2/25=1`