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lim(xto0) |x|...

`lim_(xto0) |x|`

Text Solution

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We see that when `xto0, |x|to0`
Let us establish this using `epsilon-delta` technique. Let `epsilongt0` we seek a `deltagt0` depending on
`epsilons.t. |x-0|epsilon implies||x|-0|let epsilon`
Now `||x|-o|=||x||=|x|ltdelta`
Choosing `epsilon=delta` we have
`|x|topsoil implies||x|-0|ltepsilon`
`therefore lim_(xto0)|x|=0`
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