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lim(xtosqrt3)[x]...

`lim_(xtosqrt3)[x]`

Text Solution

Verified by Experts

L.H.L.`=lim_(xtosqrt3-)[x]=lim_(hto0)[sqrt3-h]=1`
R.H.L.`=lim_(xtosqrt3+)[x]=lim_(hto0)[sqrt3+h]=1`
Thus L.H.L., R.H.L. both
exist and L.H.L.=R.H.L.
So the limit exists and it's value is 1.
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