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lim(xto-2)[x]...

`lim_(xto-2)[x]`

Text Solution

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L.H.L.`=lim_(xto-2-)(x-2)/|x-2|`
`=lim_(hto0)[-2-h]=-3`
R.H.L.`=lim_(xto-2+)[x]=lim_(hto0)[-2+h]=-2`
Thus `L.H.L.neR.H.L.`
So the limit does not exist.
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