A coin is tossed three times. Find the probability of getting at least 2 heads

Answer

A coin is tossed three times. `S={HHH,HT T, HTH,THH,T TH, THT,HHT,T T T}`
`|S|=8`
Let C be the event of getting at least 2 heads
`thereforeC={HTH,THH,HHT,HHH}`
`implies |C|=4`
`therefore P(C)=|C|/|S|=4/8=1/2`