Circle from 3 Point|Touching Axes#!#Intercepts made on Axes

Reduce the equation 2x-3y+5z+4=0 to intercept form and find the intercepts made by it on the coordinate axes.

Reduce the equation of the plane 4x-3y+2z=12 to the intercept form, and hence find the intercepts made by the plane with the coordinate axes.

Reduce the equation of the plane 2x-3y+z=6 to intercept from and find its intercepts on the coordinates axes.

Find the equation of the circle drawn on the intercept made by the line 2x+3y=6 between the coordinate axes as diameter.

The equation of the circle of radius 5 and touching the coordinates axes in third quadrant, is

Equation of the circle through the origin and making intercepts of 3 and 4 on the positive sides of the axes is

Find the equaiton of the circle drawn on the intercept between the axes made by the line 3x+4y=12 as a diameter.

Find the equaiton of the circle drawn on the intercept between the axes made by the line 3x+4y=12 as a diameter.