एक पिंड का संवेग 20 % बढ़ने से उसकी गतिज ऊर्जा में प्रतिशत वृद्धि होगी

Options

A. a. 69
B. b. 44
C. c. 48
D. d. 64

Answer

B

Explanation

`K= p^(2)//2m`
`therefore K+ Delta K= ((p^(2) + Deltap^(2)))/(2m)`
`because Deltap= 0.2p`
`K + Delta K = ((1.2p)^(2))/(2m)= (1.44p^(2))/(2m)`
`Delta K= (144p^(2))/(2m)- (p^(2))/(2m) (because K= (p^(2))/(2m))`
`Delta K= (0.44p^(2))/(2m)`
`therefore (Delta K)/(K)= 0.44 = 44%`