The given diagram represents a screw gauge. The circular scale is divided into `50` divisions and the linear scale is divided into millimeters. If the screw advances by `1 mm` when the circular scale makes `2` complete revolutions, find the least count of the instrument and the reading of the instrument in the figure.
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Answer

A, B, C

Explanation

Pitch of the screw = `(1 mm)/ 2`
= `0.5 mm`
Least count = `(0.5)/(50)`
= `0.01 mm`
Reading = Linear scale reading
+ (coinciding circular scale `xx` least count)
= `3.0 mm +(32 xx 0.01) = 3.0 + 0.32`
= `3.32 mm`.