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Using mass (M), "length"(L) , time (T) a...

Using `mass (M), "length"(L) , time (T)` and current` (A) `as fundamental quantites the demension of permeability is

A

`[M^(-1)LT^(-2)A]`

B

`[ML^(-2)T^(-2)A^(-1)]`

C

`[MLT^(-2)A^(-2)]`

D

`[MLT^(-1)A^(-1)]`

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The correct Answer is:
To find the dimension of permeability using mass (M), length (L), time (T), and current (A) as fundamental quantities, we can follow these steps: ### Step 1: Understand the relationship involving permeability We know that the speed of light \( c \) is related to permeability \( \mu_0 \) and permittivity \( \epsilon_0 \) by the equation: \[ c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \] From this equation, we can express permeability as: \[ \mu_0 = \frac{1}{c^2 \epsilon_0} \] ### Step 2: Determine the dimensions of speed of light \( c \) The dimension of speed \( c \) is given by: \[ [c] = [L^1 T^{-1}] \] ### Step 3: Find the dimensions of permittivity \( \epsilon_0 \) Using the formula for the force between two charges, we have: \[ F = \frac{1}{4\pi \epsilon_0} \frac{q_1 q_2}{r^2} \] From this, we can rearrange to find \( \epsilon_0 \): \[ \epsilon_0 = \frac{q_1 q_2}{F r^2} \] ### Step 4: Determine the dimensions of charge \( q \) The dimension of electric charge \( q \) can be expressed in terms of current and time: \[ [q] = [A^1 T^1] \] ### Step 5: Substitute the dimensions into the equation for \( \epsilon_0 \) Now substituting the dimensions into the equation for \( \epsilon_0 \): \[ [\epsilon_0] = \frac{[q]^2}{[F][r^2]} = \frac{(A^1 T^1)^2}{[M L T^{-2}][L^2]} = \frac{A^2 T^2}{M L^3} \] ### Step 6: Substitute \( \epsilon_0 \) into the equation for \( \mu_0 \) Now substituting \( [\epsilon_0] \) back into the equation for \( \mu_0 \): \[ [\mu_0] = \frac{1}{[c^2][\epsilon_0]} = \frac{1}{[L^2 T^{-2}][\frac{A^2 T^2}{M L^3}]} \] ### Step 7: Simplify the expression for \( \mu_0 \) Now we simplify: \[ [\mu_0] = \frac{1}{[L^2 T^{-2}] \cdot [\frac{A^2 T^2}{M L^3}]} = \frac{M L^3}{A^2 T^4} \] ### Step 8: Final expression for dimensions of permeability Thus, the dimensions of permeability \( \mu_0 \) are: \[ [\mu_0] = [M^1 L^1 T^{-2} A^{-2}] \] ### Conclusion The dimension of permeability is: \[ [M^1 L^1 T^{-2} A^{-2}] \]

To find the dimension of permeability using mass (M), length (L), time (T), and current (A) as fundamental quantities, we can follow these steps: ### Step 1: Understand the relationship involving permeability We know that the speed of light \( c \) is related to permeability \( \mu_0 \) and permittivity \( \epsilon_0 \) by the equation: \[ c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \] From this equation, we can express permeability as: ...
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