If `vecA,vecB,vecC` are mutually perpendicular show that `vecCxx(vecAxxvecB)=0`. Is the converse true?

Explanation

To solve the problem, we need to show that if vectors \(\vec{A}\), \(\vec{B}\), and \(\vec{C}\) are mutually perpendicular, then \(\vec{C} \times (\vec{A} \times \vec{B}) = 0\).

### Step-by-Step Solution:

1. **Understanding the Cross Product**:
The cross product of two vectors \(\vec{A}\) and \(\vec{B}\), denoted as \(\vec{A} \times \vec{B}\), results in a vector that is perpendicular to both \(\vec{A}\) and \(\vec{B}\).

2. **Finding \(\vec{A} \times \vec{B}\)**:
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