Velocity of a particle moving in a straight line varies with its displacement as `v=(sqrt(4 +4s))m//s.` Displacement of particle at time `t =0` is `s = 0`. Find displacement of particle at time `t=2 s`.

Explanation

To solve the problem, we need to find the displacement of a particle at time \( t = 2 \) seconds, given that its velocity varies with displacement as \( v = \sqrt{4 + 4s} \) m/s and that the initial displacement at \( t = 0 \) is \( s = 0 \).

### Step-by-Step Solution:

1. **Square the Velocity Equation**:
\[ v = \sqrt{4 + 4s} \]
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