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The motion of a particle along a straigh...

The motion of a particle along a straight line is described by the function `x=(2t -3)^2,` where x is in metres and t is in seconds. Find
(a) the position, velocity and acceleration at `t=2 s.`
(b) the velocity of the particle at origin.

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
(a) Position, `x=(2t-3)^2`
velocity, `v=(dx)/(dt)=4(2t-3) m//s`
and accleration, `a=(dv)/(dt)=8 m//s^2`
At `t=2s,`
`x=(2xx2-3)^2`
`=1.0 m`
`v=4(2xx2-3)`
`=4 m//s`
and `=8 m//s^2`
(b) At origin, `x=0`
or `(2t-3)=0`
`:. v=4xx0=0`
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