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Assertion : Displacement-time graph is a...

Assertion : Displacement-time graph is a parabola corresponding to straight line velocity-time graph.
Reason : lf `v= u +at` then `s= ut+ 1/2 at^2`

A

If the both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

If Assertion is true, but the Reason is false.

D

If Assertion is false but the Reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question, we will analyze both the assertion and the reason step by step. ### Step 1: Understand the Assertion The assertion states that the displacement-time graph is a parabola corresponding to a straight line velocity-time graph. ### Step 2: Analyze the Velocity-Time Graph A straight line in a velocity-time (VT) graph indicates that the velocity is either constant or changing at a uniform rate (constant acceleration). If the line is horizontal, the velocity is constant. If it has a slope, it indicates constant acceleration. ### Step 3: Determine the Nature of the Displacement-Time Graph If the velocity is constant (which corresponds to a horizontal line in the VT graph), the displacement-time (DT) graph will be a straight line. This is because displacement is calculated as: \[ s = ut + \frac{1}{2} a t^2 \] If acceleration \( a = 0 \) (which is the case for a horizontal line in the VT graph), the equation simplifies to: \[ s = ut \] This shows that the displacement increases linearly with time, resulting in a straight line. If the VT graph has a constant slope (indicating constant acceleration), then the displacement-time graph will be a parabola, as the displacement will depend on the square of time due to the \( \frac{1}{2} a t^2 \) term. ### Step 4: Conclusion on the Assertion Given that the assertion claims that the displacement-time graph is a parabola corresponding to a straight line velocity-time graph, and we have established that a straight line VT graph (with zero acceleration) results in a straight line DT graph, the assertion is **false**. ### Step 5: Analyze the Reason The reason states: \[ v = u + at \] \[ s = ut + \frac{1}{2} at^2 \] These are standard equations of motion. They are indeed true and valid for uniformly accelerated motion. ### Step 6: Conclusion on the Reason The reason is true as it correctly represents the equations of motion. ### Final Conclusion - **Assertion**: False (displacement-time graph is a straight line for a constant velocity). - **Reason**: True (the equations of motion are correct). ### Answer The correct answer is that the assertion is false, but the reason is true. ---

To solve the given question, we will analyze both the assertion and the reason step by step. ### Step 1: Understand the Assertion The assertion states that the displacement-time graph is a parabola corresponding to a straight line velocity-time graph. ### Step 2: Analyze the Velocity-Time Graph A straight line in a velocity-time (VT) graph indicates that the velocity is either constant or changing at a uniform rate (constant acceleration). If the line is horizontal, the velocity is constant. If it has a slope, it indicates constant acceleration. ...
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