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A particle is projected vertically upwar...

A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time `t (lt T)` will be

A

`g (t-T)^2`

B

`H - g (t-T)^2`

C

`1/2 g (t-T)^2`

D

`H - 1/2 g (T-t)^2`

Text Solution

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The correct Answer is:
To solve the problem of finding the height of a particle projected vertically upwards at any time \( t \) (where \( t < T \)), we can follow these steps: ### Step 1: Understand the motion of the particle When a particle is projected upwards, it moves against the force of gravity until it reaches its maximum height \( H \) at time \( T \). At this point, its velocity becomes zero. ### Step 2: Use the equations of motion We can use the second equation of motion to find the distance covered by the particle in time \( t \): \[ s = ut + \frac{1}{2} a t^2 \] where: - \( s \) is the distance traveled, - \( u \) is the initial velocity, - \( a \) is the acceleration (which is \( -g \) for upward motion), - \( t \) is the time. Since the particle is projected upwards, the initial velocity \( u \) can be expressed in terms of the maximum height \( H \) and time \( T \): \[ u = gT \] This is because the particle will have a velocity \( u \) at \( t = 0 \) and will decelerate due to gravity until it reaches the maximum height. ### Step 3: Calculate the distance traveled in time \( t \) Using the equation of motion: \[ s = gTt - \frac{1}{2} g t^2 \] This gives us the distance traveled upwards in time \( t \). ### Step 4: Find the height at time \( t \) The height \( h \) of the particle at time \( t \) can be calculated as: \[ h = H - s \] Substituting for \( s \): \[ h = H - \left( gTt - \frac{1}{2} g t^2 \right) \] Since \( H = \frac{1}{2} g T^2 \) (the total height reached at time \( T \)), we can substitute \( H \) into the equation: \[ h = \frac{1}{2} g T^2 - \left( gTt - \frac{1}{2} g t^2 \right) \] Simplifying this: \[ h = \frac{1}{2} g T^2 - gTt + \frac{1}{2} g t^2 \] \[ h = \frac{1}{2} g (T^2 - 2Tt + t^2) \] \[ h = \frac{1}{2} g (T - t)^2 \] ### Final Equation Thus, the height of the particle at any time \( t \) is given by: \[ h = H - \frac{g}{2} (T - t)^2 \]

To solve the problem of finding the height of a particle projected vertically upwards at any time \( t \) (where \( t < T \)), we can follow these steps: ### Step 1: Understand the motion of the particle When a particle is projected upwards, it moves against the force of gravity until it reaches its maximum height \( H \) at time \( T \). At this point, its velocity becomes zero. ### Step 2: Use the equations of motion We can use the second equation of motion to find the distance covered by the particle in time \( t \): \[ ...
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