A ball is projecte with a velocity 20 ms...

A ball is projecte with a velocity `20 ms^-1` at an angle to the horizontal. In order to have the maximum range. Its velocity at the highest position must be

`10 ms^-1`

`14ms^-1`

`18ms^-1`

`16ms^-1`

Text Solution

Verified by Experts

The correct Answer is:

At `45^@` , range is maximum. At highest point, it has only horizontal component of velocity or `20cos45^@ = 14 m//s` .

Topper's Solved these Questions

PROJECTILE MOTION
DC PANDEY ENGLISH|Exercise Level - 1 Subjective|21 Videos
PROJECTILE MOTION
DC PANDEY ENGLISH|Exercise Level - 2 Single Correct|10 Videos
PROJECTILE MOTION
DC PANDEY ENGLISH|Exercise Level - 1 Assertion And Reason|10 Videos
MOTION IN A PLANE
DC PANDEY ENGLISH|Exercise (C )Medical entrances gallery|32 Videos
PROPERTIES OF MATTER
DC PANDEY ENGLISH|Exercise Integer|8 Videos

Similar Questions

Explore conceptually related problems

A body is projected with a speed (u) at an angle to the horizontal to have maximum range. What is its velocity at the highest point ?

A body is projected with an initial Velocity 20 m/s at 60° to the horizontal. Its velocity after 1 sec is

A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is

A body of mass 2 kg is projected at 20 ms^(-1) at an angle 60^(@) above the horizontal. Power due to the gravitational force at its highest point is

A body is projected horizontally with a velocity of u ms^(-1) at an angle theta with the horizontal. The kinetic energy at intial the highest point is (3)/(4)th of the kinetic energy. The value of theta is :

A particle of mass m is projected with a velocity v at an angle of theta with horizontal. The angular momentum of the particle at the highest point of its trajectory is equal to :

A ball is projected with a velocity 20 sqrt(3) ms^(-1) at angle 60^(@) to the horizontal. The time interval after which the velocity vector will make an angle 30^(@) to the horizontal is (Take, g = 10 ms^(-2))

A particle of mass.m. is projected with a velocity .u. at an angle . theta . with the horizontal. Work done by gravity during its descent from its highest point to a point which is at half the maximum height is

An object is projected with a velocity of 30 ms^(-1) at an angle of 60^(@) with the horizontal. Determine the horizontal range covered by the object.

A body is projected with velocity 24 ms^(-1) making an angle 30° with the horizontal. The vertical component of its velocity after 2s is (g=10 ms^(-1) )

DC PANDEY ENGLISH-PROJECTILE MOTION-Level - 1 Single Correct

Identify the correct statement related to the projectile motion.
Text Solution
|
Two bodies are thrown with the same initial velocity at angles theta ...
Text Solution
|
The range of a projectile at an angle theta is equal to half of the ma...
Text Solution
|
A ball is projecte with a velocity 20 ms^-1 at an angle to the horizon...
Text Solution
|
A particular has initial velocity , v=3hati+4hatj and a constant force...
Text Solution
|
A body is projected at an angle 60^@ with horizontal with kinetic ener...
Text Solution
|
If T1 and T2 are the times of flight for two complementary angles, the...
Text Solution
|
A gun is firing bullets with velocity v0 by rotating it through 360^@ ...
Text Solution
|
A grass hopper can jump maximum distance 1.6m. It spends negligible ti...
Text Solution
|
Two stones are projected with the same speed but making different angl...
Text Solution
|
A ball is projected upwards from the top of a tower with a velocity 50...
Text Solution
|
Average velocity of a particle in projectile motion between its starti...
Text Solution
|
A train is moving on a track at 30ms^-1. A ball is thrown from it perp...
Text Solution
|
A body is projected at time t = 0 from a certain point on a planet's s...
Text Solution
|
A particle is fired horizontally form an inclined plane of inclination...
Text Solution
|
A fixed mortar fires a bomb at an angle of 53^@ above the horizontal w...
Text Solution
|