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A shell fired from the base of a mountai...

A shell fired from the base of a mountain just clears it. If `alpha` is the angle of projection, then the angular elevation of the summit `beta` is

A

`alpha/2`

B

`tan^(-1)(1/2)`

C

`tan^-1 ((tanalpha)/2)`

D

`tan^(-1)(2tanalpha)`

Text Solution

Verified by Experts

The correct Answer is:
C
`tan beta = H/(R//2) = (2H)/R`
`=((2u^2sin^2alpha)//(2g))/((2u^2sinalphacosalpha)//g) = (tan alpha)/2`
`:. beta = tan^(-1)((tanalpha)/2)`
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