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A ball is dropped from a height of 49 m....

A ball is dropped from a height of 49 m. The wind is blowing horizontally. Due to wind a constant horizontal acceleration is provided to the ball. Choose the correct statement (s).

A

Path of the ball is a straight line

B

Path of the ball is a curved one

C

The time taken by the ball to reach the ground is 3.16 s

D

Actual distance travelled by the ball is more then 49 m.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the motion of the ball dropped from a height of 49 m under the influence of gravity and horizontal acceleration due to wind. ### Step 1: Understanding the Motion The ball is dropped from a height of 49 m, which means it has an initial vertical velocity (u) of 0 m/s. The only force acting on it in the vertical direction is gravity, which accelerates it downwards at approximately 9.81 m/s² (we can approximate this as 10 m/s² for simplicity). ### Step 2: Analyzing Horizontal Motion The wind provides a constant horizontal acceleration (let's denote it as \( a \)). Since the ball is dropped, it starts with an initial horizontal velocity of 0 m/s. The horizontal motion is independent of the vertical motion. ### Step 3: Path of the Ball The ball will follow a parabolic trajectory due to the combination of vertical motion (under gravity) and horizontal motion (due to wind). Therefore, the path of the ball will not be a straight line; it will be a curved path. ### Step 4: Time to Reach the Ground To find the time taken for the ball to reach the ground, we can use the second equation of motion for the vertical direction: \[ s = ut + \frac{1}{2} a t^2 \] Where: - \( s = 49 \) m (the height from which the ball is dropped) - \( u = 0 \) m/s (initial vertical velocity) - \( a = g = 10 \) m/s² (acceleration due to gravity) Substituting the values: \[ 49 = 0 + \frac{1}{2} \times 10 \times t^2 \] \[ 49 = 5t^2 \] \[ t^2 = \frac{49}{5} = 9.8 \] \[ t = \sqrt{9.8} \approx 3.16 \text{ seconds} \] ### Step 5: Distance Travelled The actual distance travelled by the ball will be more than 49 m because it follows a curved path. The vertical distance is the height dropped (49 m), but the horizontal motion due to wind means the ball travels along a longer path (the hypotenuse of the triangle formed by the vertical and horizontal distances). ### Conclusion Based on the analysis: - **Statement A**: The path of the ball is a straight line. (Incorrect) - **Statement B**: The path of the ball is a curved line. (Correct) - **Statement C**: The time taken by the ball to reach the ground is approximately 3.16 seconds. (Correct) - **Statement D**: The actual distance travelled by the ball is more than 49 meters. (Correct) ### Correct Statements Therefore, the correct statements are B, C, and D.

To solve the problem step by step, we will analyze the motion of the ball dropped from a height of 49 m under the influence of gravity and horizontal acceleration due to wind. ### Step 1: Understanding the Motion The ball is dropped from a height of 49 m, which means it has an initial vertical velocity (u) of 0 m/s. The only force acting on it in the vertical direction is gravity, which accelerates it downwards at approximately 9.81 m/s² (we can approximate this as 10 m/s² for simplicity). ### Step 2: Analyzing Horizontal Motion The wind provides a constant horizontal acceleration (let's denote it as \( a \)). Since the ball is dropped, it starts with an initial horizontal velocity of 0 m/s. The horizontal motion is independent of the vertical motion. ...
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