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Two inclined planes OA and OB intersect ...

Two inclined planes OA and OB intersect in a horizontal plane having their inclinations `alpha and beta` with the horizontal as shown in figure. A particle is projected from P with velocity u along a direction perpendicular to plane OA. The particle strikes plane OB perpendicularly at Q.

If `alpha = 30^@ , beta = 30^@` and a = 4.9 m, the initial velocity of projection is

A

`9.8 ms^(-1)`

B

`4.9 ms^(-1)`

C

`4.9 (sqrt 2)ms^(-1)`

D

`19.6 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`PQ = "range" = 2(PM) = 2a cos 30^@`
`= (2)(4.9)(sqrt3/2)`
`=4.9 sqrt(3) m`
`= (u^2sin2(60^@))/9.8`
`:. 4.9(sqrt3) = (u^(2)(sqrt(3)//2))/(9.8)`
`:. u = 9.8 m//s`.
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