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Assertion: Velocity and acceleration of ...

Assertion: Velocity and acceleration of a particle in circular motion at some instant are:
`v=(2hat(i))ms^(-1)` and `a=(-hat(i)+2hat(j))ms^(-2)` , then radius of circle is `2m` .
Reason: Speed of particle is decreasing at a rate of `1ms^(-2)` .

A

If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

If Assertion is true, true but the Reason is false.

D

If Assertion is false but the Reason is true.

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze both the assertion and the reason provided in the question. ### Step 1: Analyze the Assertion The assertion states that the velocity \( \mathbf{v} \) and acceleration \( \mathbf{a} \) of a particle in circular motion are given as: - \( \mathbf{v} = 2 \hat{i} \, \text{m/s} \) - \( \mathbf{a} = -\hat{i} + 2\hat{j} \, \text{m/s}^2 \) We need to determine if the radius of the circle is indeed \( 2 \, \text{m} \). ### Step 2: Calculate the Radius For a particle in circular motion, the radial (centripetal) acceleration \( a_r \) is given by the formula: \[ a_r = \frac{v^2}{r} \] where \( v \) is the speed of the particle and \( r \) is the radius of the circular path. From the velocity given: \[ |\mathbf{v}| = 2 \, \text{m/s} \] Now, substituting the values into the radial acceleration formula: \[ a_r = \frac{(2)^2}{r} = \frac{4}{r} \] ### Step 3: Find the Total Acceleration The total acceleration \( \mathbf{a} \) is given as: \[ \mathbf{a} = -\hat{i} + 2\hat{j} \, \text{m/s}^2 \] To find the magnitude of the total acceleration: \[ |\mathbf{a}| = \sqrt{(-1)^2 + (2)^2} = \sqrt{1 + 4} = \sqrt{5} \, \text{m/s}^2 \] ### Step 4: Identify the Radial Component of Acceleration The radial component of acceleration \( a_r \) can be identified as the component of acceleration that is directed towards the center of the circular path. In this case, the radial component is: \[ a_r = -\hat{i} \, \text{m/s}^2 \quad \text{(which has a magnitude of 1 m/s}^2\text{)} \] ### Step 5: Equate the Radial Acceleration We can now equate the radial acceleration to the expression we derived: \[ 1 = \frac{4}{r} \] Solving for \( r \): \[ r = 4 \, \text{m} \] ### Step 6: Conclusion on the Assertion The assertion states that the radius is \( 2 \, \text{m} \), but our calculation shows that the radius is \( 4 \, \text{m} \). Therefore, the assertion is **false**. ### Step 7: Analyze the Reason The reason states that the speed of the particle is decreasing at a rate of \( 1 \, \text{m/s}^2 \). From the acceleration components: - The x-component of acceleration is \( -1 \, \text{m/s}^2 \), which indicates that the speed in the x-direction is decreasing at that rate. ### Step 8: Conclusion on the Reason The reason is **true** because the negative x-component of acceleration indicates a decrease in speed in that direction. ### Final Conclusion - Assertion: **False** - Reason: **True**

To solve the problem, we need to analyze both the assertion and the reason provided in the question. ### Step 1: Analyze the Assertion The assertion states that the velocity \( \mathbf{v} \) and acceleration \( \mathbf{a} \) of a particle in circular motion are given as: - \( \mathbf{v} = 2 \hat{i} \, \text{m/s} \) - \( \mathbf{a} = -\hat{i} + 2\hat{j} \, \text{m/s}^2 \) We need to determine if the radius of the circle is indeed \( 2 \, \text{m} \). ...
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