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A particle is moving in a circular path ...

A particle is moving in a circular path with a constant speed. If `theta` Is the angular displacement, then starting from `theta=0` , the maximum and minimum change in the linear momentum will occur when value of `theta` is respectively

A

`45^(@)` and `90^(@)`

B

`90^(@)` and `180^(@)`

C

`180^(@)` and `360^(@)`

D

`90^(@)` and `270^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the change in linear momentum of a particle moving in a circular path with constant speed as it undergoes angular displacement. ### Step-by-Step Solution: 1. **Understanding Linear Momentum**: The linear momentum \( P \) of a particle is given by the formula: \[ P = m \cdot v \] where \( m \) is the mass of the particle and \( v \) is its speed. 2. **Initial Momentum at \( \theta = 0^\circ \)**: At \( \theta = 0^\circ \), the particle is at a certain point on the circular path. We can denote the initial momentum as: \[ P_1 = m \cdot v \] 3. **Final Momentum at \( \theta = 180^\circ \)**: When the particle moves to \( \theta = 180^\circ \), it is directly opposite to its initial position. The direction of its velocity vector will also be opposite. Therefore, the final momentum can be expressed as: \[ P_2 = -m \cdot v \] 4. **Calculating Change in Momentum at \( \theta = 180^\circ \)**: The change in momentum \( \Delta P \) when the particle moves from \( \theta = 0^\circ \) to \( \theta = 180^\circ \) is: \[ \Delta P = P_2 - P_1 = (-m \cdot v) - (m \cdot v) = -2m \cdot v \] The magnitude of this change is: \[ |\Delta P| = 2m \cdot v \] 5. **Final Momentum at \( \theta = 360^\circ \)**: When the particle completes a full circle and returns to \( \theta = 360^\circ \), its momentum will be the same as at \( \theta = 0^\circ\): \[ P_2 = m \cdot v \] 6. **Calculating Change in Momentum at \( \theta = 360^\circ \)**: The change in momentum at this position is: \[ \Delta P = P_2 - P_1 = (m \cdot v) - (m \cdot v) = 0 \] Therefore, the magnitude of this change is: \[ |\Delta P| = 0 \] 7. **Conclusion**: From the calculations, we find that: - The maximum change in linear momentum occurs at \( \theta = 180^\circ \) with a value of \( 2m \cdot v \). - The minimum change in linear momentum occurs at \( \theta = 360^\circ \) with a value of \( 0 \). ### Final Answer: - Maximum change in linear momentum occurs at \( \theta = 180^\circ \). - Minimum change in linear momentum occurs at \( \theta = 360^\circ \).

To solve the problem, we need to analyze the change in linear momentum of a particle moving in a circular path with constant speed as it undergoes angular displacement. ### Step-by-Step Solution: 1. **Understanding Linear Momentum**: The linear momentum \( P \) of a particle is given by the formula: \[ P = m \cdot v ...
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