A small particle of mass `m` attached with a light inextensible thread of length `L` is moving in a vertical circle. In the given case particle is moving in complete vertical circle and ratio of its maximum to minimum velocity is `2:1` .
Kinetic energy of the particle at the lower most position is

Options

A. `(a)(4mgL)/(3)`
B. `(b)2mgL`
C. `(c)(8mgL)/(3)`
D. `(d)(2mgL)/(3)`

Answer

C

Explanation

`u_(max)=2u_(min)=4sqrt((gL)/(3))`
:. `K_(max)=(1)/(2)mu_(max)^(2)=(8mgL)/(3)`