if `l_(1)` is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and `l_(2)` te moment of inertia of the ring formed by the same rod about an axis passing through the centre of mass of the ring and perpendicular tot he plane of the ring. then find the ratio `(l_(1))/(l_(2))`.

Explanation

To find the ratio of the moment of inertia of a thin rod (L1) to that of a ring formed by the same rod (L2), we can follow these steps:

### Step 1: Calculate the Moment of Inertia of the Rod (L1)
The moment of inertia of a thin rod about an axis perpendicular to its length and passing through its center of mass is given by the formula:
\[ L_1 = \frac{1}{12} M L^2 \]
where \( M \) is the mass of the rod and \( L \) is its length.
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