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A flywheel of moment of inertia 5.0kg-m^...

A flywheel of moment of inertia `5.0kg-m^(2)` is rotated at a speed of `10rad//s` because of the friction at the axis it comes to rest in 10s. Find the average torque of the friction.

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To solve the problem of finding the average torque of the friction acting on the flywheel, we can follow these steps: ### Step 1: Identify the given values - Moment of inertia (I) = 5.0 kg·m² - Initial angular speed (ω₀) = 10 rad/s - Final angular speed (ω) = 0 rad/s (since it comes to rest) - Time (t) = 10 s ...
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