A solid body rotates about a stationary axis accordig to the law `theta=6t-2t^(3)`. Here `theta`, is in radian and `t` in seconds. Find
(a). The mean values of thhe angular velocity and angular acceleration averaged over the time interval between `t=0` and the complete stop.
(b). The angular acceleration at the moment when the body stops.
Hint: if `y=y(t)`. then mean/average value of `y` between `t_(1)` and `t_(2)` is `ltygt=(int_(t_(1))^(t_(2))y(t)dt))/(t_(2)-t_(1))`

Explanation

To solve the problem step by step, we will break it down into two parts as given in the question.

### Given:
The angular displacement is given by the equation:
\[ \theta = 6t - 2t^3 \]
where \(\theta\) is in radians and \(t\) is in seconds.
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