A body rotating at `20rad//s` is acted upon by a constant torque providing it a deceleration of `2rad//s^(2)`. At what time will the body have kinetic energy same as the initial value if thhe torque continues to act?

Explanation

To solve the problem, we need to determine the time at which the kinetic energy of the body becomes equal to its initial kinetic energy while it is experiencing a constant torque that causes a deceleration. Here’s a step-by-step solution:

### Step 1: Identify the given values
- Initial angular velocity, \( \omega_0 = 20 \, \text{rad/s} \)
- Angular deceleration (due to torque), \( \alpha = 2 \, \text{rad/s}^2 \)

### Step 2: Understand the relationship between kinetic energy and angular velocity
The kinetic energy \( K \) of a rotating body is given by the formula:
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