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A wheel whose moment of inertial is 0.03...

A wheel whose moment of inertial is `0.03kgm^(2)`, is accelerated from rest to `20rad//s` in 5 s. When the external torque is removed, the wheel stops in 1 min. Find
(a). The frictional torque.
(b). The external torque.

Text Solution

AI Generated Solution

To solve the problem, we need to find the frictional torque and the external torque acting on the wheel. We will break down the solution into steps. ### Given Data: - Moment of Inertia, \( I = 0.03 \, \text{kg m}^2 \) - Final angular velocity, \( \omega_f = 20 \, \text{rad/s} \) - Initial angular velocity, \( \omega_i = 0 \, \text{rad/s} \) (starts from rest) - Time taken to accelerate, \( t = 5 \, \text{s} \) - Time taken to stop after removing external torque, \( t_{stop} = 1 \, \text{min} = 60 \, \text{s} \) ...
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