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A shaft is turning at 65rad//s at time z...

A shaft is turning at `65rad//s` at time zero. Thereafter, angular acceleration is given by `alpha=-10rad//s^(2)-5trad//s^(2)`
Where `t` is the elapsed time
(a). Find its angular speed at `t=3.0` s
(b). How much angle does it turn in these `3s`?

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into two parts as specified in the question. ### Part (a): Find the angular speed at \( t = 3.0 \, s \) 1. **Given Information**: - Initial angular speed, \( \omega_0 = 65 \, \text{rad/s} \) - Angular acceleration, \( \alpha = -10 - 5t \, \text{rad/s}^2 \) ...
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