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The radius of gyration of a disc of radi...

The radius of gyration of a disc of radius 25 cm about a centroidal axis perpendicular to disc is a) 18 cm b) 12.5 cm c) 36 cm d) 50 cm

A

18 cm

B

12.5 cm

C

36 cm

D

50 cm

Text Solution

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The correct Answer is:
To find the radius of gyration (k) of a disc about a centroidal axis perpendicular to the disc, we can follow these steps: ### Step 1: Identify the given data - The radius of the disc (r) is given as 25 cm. ### Step 2: Recall the formula for the radius of gyration The radius of gyration (k) is given by the formula: \[ k = \sqrt{\frac{I}{m}} \] where \( I \) is the moment of inertia and \( m \) is the mass of the disc. ### Step 3: Determine the moment of inertia for the disc The moment of inertia \( I \) of a disc about a centroidal axis perpendicular to the disc is given by: \[ I = \frac{1}{2} m r^2 \] where \( r \) is the radius of the disc. ### Step 4: Substitute the moment of inertia into the radius of gyration formula Substituting \( I \) into the formula for \( k \): \[ k = \sqrt{\frac{\frac{1}{2} m r^2}{m}} \] ### Step 5: Simplify the expression The mass \( m \) cancels out: \[ k = \sqrt{\frac{1}{2} r^2} \] This simplifies to: \[ k = \frac{r}{\sqrt{2}} \] ### Step 6: Substitute the value of r Now, substituting the value of \( r = 25 \) cm: \[ k = \frac{25}{\sqrt{2}} \] ### Step 7: Calculate the value of k Calculating \( \sqrt{2} \): \[ \sqrt{2} \approx 1.414 \] Now, substituting this value: \[ k \approx \frac{25}{1.414} \approx 17.68 \, \text{cm} \] ### Step 8: Final answer The radius of gyration of the disc about the centroidal axis perpendicular to the disc is approximately 17.68 cm. Thus, the correct option is: **Option A: 18 cm (approximately)** ---

To find the radius of gyration (k) of a disc about a centroidal axis perpendicular to the disc, we can follow these steps: ### Step 1: Identify the given data - The radius of the disc (r) is given as 25 cm. ### Step 2: Recall the formula for the radius of gyration The radius of gyration (k) is given by the formula: \[ k = \sqrt{\frac{I}{m}} \] ...
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DC PANDEY ENGLISH-ROTATIONAL MECHANICS-Level 1 Objective
  1. The moment of inertia of a body does not depend on

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  2. The radius of gyration of a disc of radius 25 cm about a centroidal ax...

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  3. A shaft initially rotating at 1725 rpm is brought to rest uniformly in...

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  4. A man standing on a platform holds weights in his outstretched arms. T...

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  5. Moment of inertia of a thin semicircular disc (mass - M & radius = R) ...

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  6. Two bodies A and B made of same material have the moment of inertial i...

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  7. When a sphere rolls down an inclined plane, then identity the correct ...

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  8. A circular table rotates about a vertical axis with a constant angular...

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  9. If R is the radius of gyration of a body of mass M and radius r, then ...

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  10. A solid sphere rolls down two different inclined planes of the same he...

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  11. For the same total mass, which of the following will have the largest ...

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  12. A disc and a solid sphere of same mass and radius roll down an incline...

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  13. A horizontal disc rotates freely with angular velocity omega about a v...

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  14. A solid homogeneous sphere is moving on a rough horizontal surface, pa...

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  15. A particle of mass m=3kg moves along a straight line 4y-3x=2 where x a...

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  16. A solid sphere rolls without slipping on a rough horizontal floor, mov...

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  17. Let l be the moment of inertia of a uniform square plate about an axi...

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  18. A spool is pulled horizontally on rough surface by two equal and oppos...

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  19. Two identical discs are positioned on a vertical axis as shown in the ...

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  20. The moment of inertia of hollow sphere (mass M) of inner radius R and ...

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