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Let I(1) and I(2) be the moment of inert...


Let `I_(1)` and `I_(2)` be the moment of inertia of a uniform square plate about axes shown in the figure. Then the ratio `I_(1):I_(2)` is

A

`1:(1)/(7)`

B

`1:(12)/(7)`

C

`1:(7)/(12)`

D

`1:7`

Text Solution

Verified by Experts

`I_(1)=(ma^(2))/(12)`
`I_(2)=I_(1)+mr^(2)`
`=(ma^(2))/(12)+(ma^(2))/(2)`
`=(7)/(12)ma^(2)`
`thereforeI_(1):I_(2)=1:7`
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