A particle of mass `m` is projected from the ground with an initial speed `u` at an angle `alpha`. Find the magnitude of its angular momentum at the highest point of its trajector about the point of projection.

Options

A. `((m)u^(3)cosalphasin^(2)alpha)/(2g)`
B. `((m)u^(3)cosalphasin^(2)alpha)/(g)`
C. `((m)u^(3)cosalphasin^(2)alpha)/(2)`
D. `(u^(3)cosalphasin^(2)alpha)/(2g)`

Explanation

To find the magnitude of the angular momentum of a particle projected from the ground at an angle α with an initial speed u, we can follow these steps:

### Step 1: Understand the motion of the particle
The particle is projected at an angle α with an initial speed u. It will follow a parabolic trajectory and reach a maximum height (h_max) at the highest point of its trajectory.

**Hint:** Remember that at the highest point of projectile motion, the vertical component of the velocity becomes zero.

### Step 2: Determine the horizontal and vertical components of the initial velocity
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