Two forces `F_(1)` and `F_(2)` are applied on a spool of mass `M` and moment of inertia `I` about an axis passing through its centre of mass. Find the ratio `(F_(1))/(F_(2))`. So that the force of friction is zero. Given that `Ilt2Mr^(2)`.

Explanation

`a=Ralpha` by applied forces
`therefore(F_(1)+F_(2))/(M)=2r[(F_(1)(2r)-F_(2)(r))/(I)]` ltbr. Solving these two equations we get
`(F_(1))/(F_(2))=(I+2Mr^(2))/(4Mr^(2)-I)`