A solid sphere of mass 10 kg is placed on a rough surface having coefficient of frictio `mu=0.1A` constant force `F=7N` is applied along a line passing through the centre of the sphere as shown in the figure. The value of frictional force on the sphere is

Options

A. 1 N
B. 2 N
C. 3 N
D. 7 N

Explanation

Requirement of friction
`a=Ralpha`
`therefore((7-f)/(10))=((R)(f.R))/(2//5mR^(2))`
`=(2.5f)/(m)=(2.5f)/(10)`
solving this equation we get
`f=2`
Since `fltf_(max)` therefore `2N` frictional force will