A uniform solid cylinder of mass `m` and radius `R` is placed on a rough horizontal surface. A horizontal constant force `F` is applied at the top point P of the cylinder so that it start pure rolling. The acceleration of the cylinder is

Options

A. `F//3m`
B. `2F//3m`
C. `4F//3m`
D. `5F//3m`

Explanation

In case of pure rolling `alpha` can be obtained about bottommost point,
about which torque of friction is zero.
`alpha=(F(2R))/(3//2mR^(2))=(4)/(3)(F)/(mR)`
`thereforea=Ralpha=(4F)/(3m)`