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A ring of radius R rolls on a horizontal...


A ring of radius `R` rolls on a horizontal surface with constant acceleration `a` of the centre of mass as shown in figure. If `omega` is the instantaneous angular velocity of the ring. Then the net acceleration of the point of contact of the ring with gound is

A

zero

B

`omega^(2)R`

C

`a`

D

`sqrt(a^(2)+(omega^(2)R)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

`a=Ralpha`
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