A straight rod AB of mass `M` and length `L` is placed on a frictionless horizontal surface. A force having constant magnitude F and a fixed direction start acting at the end A. The rod is initially perpendicular to the force. The initial acceleration of end B is

Options

A. zero
B. `2F//M`
C. `4F//M`
D. None of these

Explanation

`a=(F)/(M)`
`alpha=(FL//2)/(ML^(2)//12)=(6F)/(ML)`
`a_(B)=(L)/(2)alpha-a=(2F)/(M)` (downward)