Equation of a transverse wave travelling in a rope is given by
`y=5sin(4.0t-0.02 x)`
where y and x are expressed in cm and time in seconds, find phase difference `DeltaPhi`.
(a) of same particle at two different times with interval of 1 s ,
(b) of two different particle located at a distance of 10cm at same time

Answer

A, B, D

Explanation

(a) `DeltaPhi=((2pi)/(T))Deltat`, but `(2pi)/(T)
=omega=4.0 rad//s`
:. `DeltaPhi= omega Deltat=(4.0)(1.0)`
`=4rad`
`DeltaPhi=((2pi)/(lambda))Deltax`, but `(2pi)/(lambda)=k=0.02cm^-1`
:. `DeltaPhi=(0.02)(10)`
`=0.2rad`