Speed of sound in air is `330m//s`.Find maximum and minimum wavelength of audible sound in air.

Explanation

To find the maximum and minimum wavelength of audible sound in air, we can follow these steps:

### Step 1: Understand the given data
- Speed of sound in air (v) = 330 m/s
- Frequency range of audible sound:
- Minimum frequency (f_min) = 20 Hz
- Maximum frequency (f_max) = 20,000 Hz (or 20 kHz)

### Step 2: Use the formula for wavelength
The relationship between speed (v), frequency (f), and wavelength (λ) is given by the formula:
\[ v = f \cdot \lambda \]
From this, we can express wavelength as:
\[ \lambda = \frac{v}{f} \]

### Step 3: Calculate the minimum wavelength
To find the minimum wavelength, we use the maximum frequency (f_max):
- \( f_{max} = 20,000 \, \text{Hz} \)

Using the formula:
\[ \lambda_{min} = \frac{v}{f_{max}} = \frac{330 \, \text{m/s}}{20,000 \, \text{Hz}} \]
Calculating this gives:
\[ \lambda_{min} = \frac{330}{20,000} = 0.0165 \, \text{m} \]

### Step 4: Calculate the maximum wavelength
To find the maximum wavelength, we use the minimum frequency (f_min):
- \( f_{min} = 20 \, \text{Hz} \)

Using the formula:
\[ \lambda_{max} = \frac{v}{f_{min}} = \frac{330 \, \text{m/s}}{20 \, \text{Hz}} \]
Calculating this gives:
\[ \lambda_{max} = \frac{330}{20} = 16.5 \, \text{m} \]

### Step 5: State the results
- Minimum wavelength (λ_min) = 0.0165 m
- Maximum wavelength (λ_max) = 16.5 m

### Final Answer:
- Minimum Wavelength: 0.0165 m
- Maximum Wavelength: 16.5 m

---