A travelling wave pulse is given by `y = (10)/(5 + (x + 2t)^(2))`
Here, `x and y` are in meter and `t` in second. In which direction and with what velocity is the pulse propagation. What is the ampitude of pulse?

Answer

A, B, C, D

Explanation

Since, coefficient of `t` and `x` are opposite signs, then wave is travelling along negative x-direction.
Further, speed of wave `=("Coefficient of t")/("Coefficient of x")`
`=(2)/(1) = m//s`
Amplitude `=` maximum value of `y`
`= (10)/(5) = 2 m`