A stretched wire is oscillating in third overtone mode. Equation of transverse stationary wave produced in this wire is
`y= A sin (6pix)sin(20pit)`
Here, x is in metres. Find the length of the wire.

Answer

B, C

Explanation

From the given equation we can see that
`k=6pim^(-1)`
` lambda= (2pi)/k = (2pi)/(6pi)`
= 1/3m
Now, third overtone mode means four loops as shown below

One loop size is `lambda/2`, therefore total length of wire,
`l=4(lambda/2) = 2lambda`
`=2(1/3) m`
` = 2/3m `