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Assertion: Ratio of maximum intensity an...

Assertion: Ratio of maximum intensity and minimum intensity in interference is `25:1`. The amplitudes ratio of two waves should be `3:2`.
Reason: `I_(max)/I_(min) = ((A_1+A_2)/(A_1-A_2))^2` .

A

If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

B

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

If Assertion is true, but the Reason is false.

D

If Assertion is false but the Reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we need to analyze the assertion and reason provided, using the formulas for maximum and minimum intensity in the context of wave interference. ### Step-by-Step Solution: 1. **Understanding the Assertion**: The assertion states that the ratio of maximum intensity \( I_{max} \) to minimum intensity \( I_{min} \) is \( 25:1 \). It also claims that the ratio of the amplitudes of two waves is \( 3:2 \). 2. **Using the Formulas**: The formulas for maximum and minimum intensity in interference are: \[ I_{max} = (A_1 + A_2)^2 \] \[ I_{min} = (A_1 - A_2)^2 \] 3. **Setting Up the Ratio**: The ratio of maximum intensity to minimum intensity can be expressed as: \[ \frac{I_{max}}{I_{min}} = \frac{(A_1 + A_2)^2}{(A_1 - A_2)^2} \] 4. **Substituting the Amplitude Ratio**: Given the amplitude ratio \( \frac{A_1}{A_2} = \frac{3}{2} \), we can express \( A_1 \) and \( A_2 \) in terms of a common variable. Let: \[ A_2 = 2k \quad \text{and} \quad A_1 = 3k \] where \( k \) is a constant. 5. **Calculating \( I_{max} \) and \( I_{min} \)**: Substitute \( A_1 \) and \( A_2 \) into the formulas: \[ I_{max} = (3k + 2k)^2 = (5k)^2 = 25k^2 \] \[ I_{min} = (3k - 2k)^2 = (1k)^2 = k^2 \] 6. **Finding the Ratio**: Now, we can find the ratio: \[ \frac{I_{max}}{I_{min}} = \frac{25k^2}{k^2} = 25 \] Therefore, the ratio \( I_{max} : I_{min} = 25 : 1 \). 7. **Conclusion about the Assertion**: Since we have shown that the ratio of maximum intensity to minimum intensity is indeed \( 25:1 \) when the amplitude ratio is \( 3:2 \), the assertion is true. 8. **Verifying the Reason**: The reason states that \( \frac{I_{max}}{I_{min}} = \left(\frac{A_1 + A_2}{A_1 - A_2}\right)^2 \). We derived this formula earlier, confirming that it is correct. 9. **Final Conclusion**: Both the assertion and the reason are true, and the reason correctly explains the assertion.
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