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The string of a violin plays a note of 4...

The string of a violin plays a note of `400 H_(Z)` at its correct tension . The string is bit taut and produces `5` beats per second with a tuning fork of frequency `400 H_(Z)` . Find frequency of the note emitted by this taut string .

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AI Generated Solution

To find the frequency of the note emitted by the taut string, we can follow these steps: ### Step 1: Understand the concept of beats When two sound waves of slightly different frequencies interfere, they produce a phenomenon called beats. The number of beats per second is equal to the absolute difference between the frequencies of the two waves. ### Step 2: Identify the given data - Frequency of the tuning fork (µ) = 400 Hz - Number of beats per second (f) = 5 beats/s ...
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