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Four sources of sound each of sound leve...

Four sources of sound each of sound level `10 dB` are sounded together in phase , the resultant intensity level will be `(log _(10) 2 = 0.3)`

A

`40 dB`

B

`26 dB`

C

`22 dB`

D

`13 dB`

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The correct Answer is:
To solve the problem of finding the resultant intensity level when four sources of sound, each at a sound level of 10 dB, are sounded together in phase, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Sound Levels**: Each sound source has a sound level of 10 dB. The sound level in decibels (dB) is related to the intensity of sound. 2. **Intensity Relationship**: The intensity level \( L \) in dB is given by the formula: \[ L = 10 \log_{10} \left( \frac{I}{I_0} \right) \] where \( I \) is the intensity of the sound and \( I_0 \) is the reference intensity. 3. **Calculating Intensity for One Source**: For one source at 10 dB: \[ 10 = 10 \log_{10} \left( \frac{I_1}{I_0} \right) \] Dividing both sides by 10: \[ 1 = \log_{10} \left( \frac{I_1}{I_0} \right) \] Therefore, \[ \frac{I_1}{I_0} = 10 \quad \Rightarrow \quad I_1 = 10 I_0 \] 4. **Calculating Total Intensity for Four Sources**: Since the sources are in phase, the intensities add up. Thus, the total intensity \( I_{total} \) from four sources is: \[ I_{total} = 4 I_1 = 4 \times 10 I_0 = 40 I_0 \] 5. **Finding Resultant Sound Level**: Now we can find the resultant sound level \( L_{total} \): \[ L_{total} = 10 \log_{10} \left( \frac{I_{total}}{I_0} \right) = 10 \log_{10} \left( \frac{40 I_0}{I_0} \right) = 10 \log_{10} (40) \] 6. **Using Logarithm Properties**: We can express 40 as \( 10 \times 4 \): \[ \log_{10} (40) = \log_{10} (10) + \log_{10} (4) = 1 + \log_{10} (4) \] Using the approximation \( \log_{10} (4) = 2 \log_{10} (2) \) and given \( \log_{10} (2) = 0.3 \): \[ \log_{10} (4) = 2 \times 0.3 = 0.6 \] Thus, \[ \log_{10} (40) = 1 + 0.6 = 1.6 \] 7. **Calculating Final Sound Level**: Therefore, \[ L_{total} = 10 \times 1.6 = 16 \text{ dB} \] Since we need to add the original sound level of 10 dB: \[ L_{final} = 10 + 16 = 26 \text{ dB} \] ### Final Answer: The resultant intensity level when four sources of sound each at 10 dB are sounded together in phase is **26 dB**.

To solve the problem of finding the resultant intensity level when four sources of sound, each at a sound level of 10 dB, are sounded together in phase, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Sound Levels**: Each sound source has a sound level of 10 dB. The sound level in decibels (dB) is related to the intensity of sound. 2. **Intensity Relationship**: ...
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DC PANDEY ENGLISH-SOUND WAVES-Level 1 Objective
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  7. Two identical wires are stretched by the same tension of 100 N and eac...

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  8. A tuning fork of frequency 340 Hz is excited and held above a cylindri...

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  9. In a closed end pipe of length 105 cm , standing waves are set up corr...

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  10. Oxygen is 16 times heavier than hydrogen. At NTP equal volumn of hydro...

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  11. A train is moving towards a stationary observer. Which of the followin...

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  12. A closed organ pipe and an open organ pipe of same length produce 4 be...

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  13. One train is approaching an observer at rest and another train is rece...

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  14. Speed of sound in air is 320 m//s . A pipe closed at one end has a len...

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  15. Four sources of sound each of sound level 10 dB are sounded together i...

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  16. A longitudinal sound wave given by p = 2.5 sin.(pi)/(2) (x - 600 t) (p...

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  17. Sound waves of frequency 600 H(Z) fall normally on perfectly reflectin...

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  18. The wavelength of two sound waves are 49 cm and 50 cm , respectively ....

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  19. Two persons A and B , each carrying a source of frequency 300 H(Z) , a...

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  20. A fixed source of sound emitting a certain frequency appears as f(a) w...

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