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Consider an 1100 particels gas system wi...

Consider an `1100` particels gas system with speeds distribution as follows :
1000 particles each with speed `100 m//s`
2000 particles each wityh speed `200 m//s`
4000 particles each with speed `300 m//s`
3000 particles each with speed `400 m//s` and 1000 particles each with speed `500 m//s`
Find the average speed, and rms speed.

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To solve the problem of finding the average speed and the root mean square (RMS) speed of a gas system with given particle speeds and their distributions, we can follow these steps: ### Step 1: Identify the given data We have the following data for the gas particles: - 1000 particles with speed \( V_1 = 100 \, \text{m/s} \) - 2000 particles with speed \( V_2 = 200 \, \text{m/s} \) - 4000 particles with speed \( V_3 = 300 \, \text{m/s} \) - 3000 particles with speed \( V_4 = 400 \, \text{m/s} \) - 1000 particles with speed \( V_5 = 500 \, \text{m/s} \) ### Step 2: Calculate the total number of particles The total number of particles \( N \) is the sum of all particles: \[ N = 1000 + 2000 + 4000 + 3000 + 1000 = 11000 \] ### Step 3: Calculate the average speed The formula for average speed \( \bar{V} \) is given by: \[ \bar{V} = \frac{N_1 V_1 + N_2 V_2 + N_3 V_3 + N_4 V_4 + N_5 V_5}{N} \] Substituting the values: \[ \bar{V} = \frac{1000 \times 100 + 2000 \times 200 + 4000 \times 300 + 3000 \times 400 + 1000 \times 500}{11000} \] Calculating each term: - \( 1000 \times 100 = 100000 \) - \( 2000 \times 200 = 400000 \) - \( 4000 \times 300 = 1200000 \) - \( 3000 \times 400 = 1200000 \) - \( 1000 \times 500 = 500000 \) Adding these values: \[ 100000 + 400000 + 1200000 + 1200000 + 500000 = 3200000 \] Now, substituting back into the average speed formula: \[ \bar{V} = \frac{3200000}{11000} \approx 290.91 \, \text{m/s} \] ### Step 4: Calculate the RMS speed The formula for RMS speed \( V_{rms} \) is given by: \[ V_{rms} = \sqrt{\frac{N_1 V_1^2 + N_2 V_2^2 + N_3 V_3^2 + N_4 V_4^2 + N_5 V_5^2}{N}} \] Substituting the values: \[ V_{rms} = \sqrt{\frac{1000 \times 100^2 + 2000 \times 200^2 + 4000 \times 300^2 + 3000 \times 400^2 + 1000 \times 500^2}{11000}} \] Calculating each term: - \( 1000 \times 100^2 = 10000000 \) - \( 2000 \times 200^2 = 80000000 \) - \( 4000 \times 300^2 = 360000000 \) - \( 3000 \times 400^2 = 480000000 \) - \( 1000 \times 500^2 = 250000000 \) Adding these values: \[ 10000000 + 80000000 + 360000000 + 480000000 + 250000000 = 1170000000 \] Now, substituting back into the RMS speed formula: \[ V_{rms} = \sqrt{\frac{1170000000}{11000}} \approx \sqrt{106363.6363} \approx 326.13 \, \text{m/s} \] ### Final Results - Average Speed \( \bar{V} \approx 290.91 \, \text{m/s} \) - RMS Speed \( V_{rms} \approx 326.13 \, \text{m/s} \)

To solve the problem of finding the average speed and the root mean square (RMS) speed of a gas system with given particle speeds and their distributions, we can follow these steps: ### Step 1: Identify the given data We have the following data for the gas particles: - 1000 particles with speed \( V_1 = 100 \, \text{m/s} \) - 2000 particles with speed \( V_2 = 200 \, \text{m/s} \) - 4000 particles with speed \( V_3 = 300 \, \text{m/s} \) - 3000 particles with speed \( V_4 = 400 \, \text{m/s} \) ...
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