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A piece of metal floats on mercury. The ...

A piece of metal floats on mercury. The coefficient of volume expansion of metal and mercury are `gamma_1 and gamma_2`, respectively. if the temperature of both mercury and metal are increased by an amount `Delta T`, by what factor does the frection of the volume of the metal submerged in mercury changes ?

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To solve the problem, we need to analyze how the fraction of the volume of the metal submerged in mercury changes when both the metal and mercury are heated by a temperature change \( \Delta T \). ### Step-by-Step Solution: 1. **Understand the Initial Condition**: - Let the density of the metal be \( \rho_s \) and the density of mercury be \( \rho_l \). - The fraction of the volume of the metal submerged in mercury can be expressed as: \[ f_0 = \frac{\rho_s}{\rho_l} \] 2. **Apply the Volume Expansion Formula**: - When the temperature increases by \( \Delta T \), the new densities of the metal and mercury can be expressed using their coefficients of volume expansion \( \gamma_1 \) and \( \gamma_2 \): \[ \rho_s' = \frac{\rho_s}{1 + \gamma_1 \Delta T} \] \[ \rho_l' = \frac{\rho_l}{1 + \gamma_2 \Delta T} \] 3. **Calculate the New Fraction**: - The new fraction of the volume of the metal submerged in mercury after the temperature increase becomes: \[ f = \frac{\rho_s'}{\rho_l'} = \frac{\frac{\rho_s}{1 + \gamma_1 \Delta T}}{\frac{\rho_l}{1 + \gamma_2 \Delta T}} = \frac{\rho_s}{\rho_l} \cdot \frac{1 + \gamma_2 \Delta T}{1 + \gamma_1 \Delta T} \] - Substituting \( f_0 \) into the equation gives: \[ f = f_0 \cdot \frac{1 + \gamma_2 \Delta T}{1 + \gamma_1 \Delta T} \] 4. **Simplify the Expression**: - For small values of \( \gamma_1 \Delta T \) and \( \gamma_2 \Delta T \) (which is often the case in thermal expansion problems), we can use the approximation: \[ \frac{1 + x}{1 + y} \approx 1 + (x - y) \quad \text{for small } x \text{ and } y \] - Applying this approximation: \[ f \approx f_0 \cdot \left(1 + (\gamma_2 - \gamma_1) \Delta T\right) \] 5. **Final Result**: - Thus, the fraction of the volume of the metal submerged in mercury changes by a factor of: \[ f \approx f_0 \cdot \left(1 + (\gamma_2 - \gamma_1) \Delta T\right) \]

To solve the problem, we need to analyze how the fraction of the volume of the metal submerged in mercury changes when both the metal and mercury are heated by a temperature change \( \Delta T \). ### Step-by-Step Solution: 1. **Understand the Initial Condition**: - Let the density of the metal be \( \rho_s \) and the density of mercury be \( \rho_l \). - The fraction of the volume of the metal submerged in mercury can be expressed as: \[ ...
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