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If nitrogen gas molecule goes straight u...

If nitrogen gas molecule goes straight up with its rms speed at `0^@ C` from the surface of the earth and there are no collisions with other molecules, then it will rise to an approximate height of.

A

`8 km`

B

`12 km`

C

`12 m`

D

`8 m`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how high a nitrogen gas molecule can rise if it goes straight up with its root mean square (RMS) speed at 0°C, we can follow these steps: ### Step-by-Step Solution: 1. **Calculate the RMS Speed (Vrms) of Nitrogen Gas:** The formula for the RMS speed is given by: \[ V_{rms} = \sqrt{\frac{3RT}{M}} \] Where: - \( R \) = Universal gas constant = \( 8.314 \, \text{J/(mol K)} \) - \( T \) = Temperature in Kelvin = \( 0°C + 273 = 273 \, \text{K} \) - \( M \) = Molar mass of nitrogen (N₂) = \( 28 \, \text{g/mol} = 28 \times 10^{-3} \, \text{kg/mol} \) Plugging in the values: \[ V_{rms} = \sqrt{\frac{3 \times 8.314 \times 273}{28 \times 10^{-3}}} \] 2. **Calculate the RMS Speed:** - Calculate the numerator: \[ 3 \times 8.314 \times 273 \approx 6810.642 \, \text{J/(kg)} \] - Calculate the denominator: \[ 28 \times 10^{-3} \approx 0.028 \, \text{kg} \] - Now calculate: \[ V_{rms} = \sqrt{\frac{6810.642}{0.028}} \approx \sqrt{243,000} \approx 493 \, \text{m/s} \] 3. **Use the Kinematic Equation to Find Maximum Height (H):** The maximum height can be calculated using the formula: \[ H = \frac{V^2}{2g} \] Where \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)). Plugging in the values: \[ H = \frac{(493)^2}{2 \times 9.81} \] 4. **Calculate the Maximum Height:** - Calculate \( (493)^2 \): \[ 493^2 \approx 243,009 \] - Now calculate: \[ H = \frac{243,009}{19.62} \approx 12,394 \, \text{m} \approx 12.4 \, \text{km} \] 5. **Consider the Effect of Decreasing g with Height:** Since the height is significant, the value of \( g \) will decrease slightly with height. Therefore, we can conclude that the approximate height the nitrogen molecule can rise is around \( 12 \, \text{km} \). ### Final Answer: The nitrogen gas molecule will rise to an approximate height of **12 km**.

To solve the problem of how high a nitrogen gas molecule can rise if it goes straight up with its root mean square (RMS) speed at 0°C, we can follow these steps: ### Step-by-Step Solution: 1. **Calculate the RMS Speed (Vrms) of Nitrogen Gas:** The formula for the RMS speed is given by: \[ V_{rms} = \sqrt{\frac{3RT}{M}} ...
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