In the process shown in figure, the internal energy of and ideal gas decreases by `(3p_0V_0)/(2)` in going from point C to A. Heat transfer along the process CA is

Options

A. (a) `(-3p_0V_0)`
B. (b) `(-5p_0V_0//2)`
C. (c) `(-3p_0V_0//2)`
D. (d) zero

Answer

B

Explanation

`Q=W+DeltaU`
=area under the graph `+DeltaU`
`=-p_0V_0-(3p_0V_0)/(2)`
`=-5/2p_0V_0`