The resistance of a thin silver wire is `1.0 Omega` at `20^@C`. The wire is placed in a liquid bath and its resistance rises to `1.2 Omega`. What is the temperature of the bath? `alpha` for silver is `3.8xx10^03//(.^(@) C)`

Explanation

To solve the problem, we need to determine the temperature of the liquid bath based on the change in resistance of a silver wire. We will use the formula that relates resistance and temperature.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Initial resistance, \( R_0 = 1.0 \, \Omega \) (at \( T_0 = 20^\circ C \))
- Final resistance, \( R_T = 1.2 \, \Omega \)
- Temperature coefficient of resistance for silver, \( \alpha = 3.8 \times 10^{-3} \, \text{°C}^{-1} \)
...